How much evidence is enough evidence?
FACT: Each card has a number on one side and a letter on the other.
HYPOTHESIS: Every card that has a vowel on one side has an even number on its opposite side.
THE TEST: Which card or cards must you turn over in order to test the Hypothesis?
(Obviously, you COULD turn over all four cards, and perhaps you must. But if you can do it with fewer, you’ll save yourself time and energy gathering your evidence.)
Type your answer in the Reply field below and Save.
The 15 possible answers are:
All four cards: G 2 3 E
Three cards: G 2 3 / G 2 E / G 3 E / 2 3 E
Just two cards: G and 2 / G and 3 / G and E / 2 and 3 / 2 and E / 3 and E
Just one card: Card G only / Card 2 only / Card 3 only / Card E only
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Counterintuitive Spring 2023 
E,2
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cards 2 and E
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Card 2 and card E because that is the only data necessary for the hypothesis.
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Only 2 and E, because we are not interested in the odd numbers or non vowels. Turning these cards over will determine if our hypothesis is correct (Vowels and even numbers are paired).
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2 and E, because your hypothesis is only looking at vowels and even numbers.
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You would flip all four cards
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Card 2, 3 & E
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cards 2 and e
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G & E because I would flip the cards that are letters for those might have numbers on the flipside
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To test the hypothesis with 4 cards you would have to turn over E and 2 because E should have an even number on the other side and 2 should have a vowel on the other side.
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Turn over card 3 and card G
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I think that two cards would be sufficient because you need to check the cards with a vowel (E) and the one with an even number (2) to see if the E card has an even number on the other side. Flipping the 2 card over to see if it has a vowel on it will verify that this hypothesis is true. If the E card has an even number on the other side, and the 2 card has a vowel on its other side, then this hypothesis is accurate.
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I would pick the cards 2, G, and E to prove the hypothesis.
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I would flip the cards with an E and 2.
Because these cards follow the hypothesis, stating that “every card that has a vowel on one side has an even number on its opposite side.”
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i would turn over the cards G and 3, to test if the hypothesis is true about having a vowel on one side and an even number on the opposite side. it is already stated that there is a vowel on E and an even number on 2
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G23E none of them are dependent on the other, therefore if you turn one over and it still complies with he hypothesis there is no way to prove based off that one card
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You would only have to flip over G and 3. 2 and E are irrelevant, E is a vowel and 2 is an even number so most likely has a vowel on the other side as well.
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E and “2” because those two cards are the only cards in which one of the two conditions is met. Flipping the other cards would be pointless as neither of the conditions are met therefore the hypothesis will be false.
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Flip 2 and E
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Only 2 and E. Flipping the other cards would not do anything to prove or disprove the hypothesis.
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If it were up to me I would choose 2, E because it will test the hypothesis to see if it is actually true.
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I would turn over G and 2. G is not a vowel so if there is an even number on the other side then the hypothesis is false. If you turn the 2 over and there is not a vowel than the hypothesis is false. However, if you turn the G around and it is an odd number and the two around and it is a vowel, then the hypothesis is correct.
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I would turn over 2 and E
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Only 2 and E because E is the only vowel and 2 is the only even number. You do not need to flip the other cards
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2 and E are the only cards that must be turned over. The hypothesis only regards vowels and even numbers, leaving the G and the 3 irrelevant to the claim.
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I would do 2 and E
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To attack this problem, I would start by simply turning over card E to see if its reverse side contains an even number. If it does not, the hypothesis is already disproven. If it does, I would then flip card 2 just to ensure that this is the case for all cards in this set.
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I would say all 4 cards must be flipped over to complete the experiment. The hypothesis is claiming that all (even numbers/vowels) must have the corresponding on the other side. To make sure this stays consistent, we have to make sure that the G/3 cards do not have a(n) (even number/vowel) on the other side. If there is a(n) (even number/vowel) on the other side, the hypothesis would be false. Regardless of the 2 and the E.
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you would have to flip 2,3, and E
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G 2 3 E
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solely E,2 because the riddle is only interested in the even numbers and vowels.
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G and E, we already see a vowel, so flipping that would confirm or deny the hypothesis, and the G would also contribute and see if the letter and the number are assigned with meaning or randomness.
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You would have to flip over card 2 and E
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You would need to flip 2 cards, E and 2
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Cards g and 2. If g becomes odd and 2 becomes a vowel, than your hypothesis is correct.
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I would do card E and 2.
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You would only need to turn over E and 2 and check if E has an even number on its back side and if 2 has a vowel on its back side, then the hypothesis is true. You don’t even need to check 3 or G because they’ve already proven irrelevant to the hypothesis because we already know at least one side doesn’t have a vowel or even number.
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It’s E and 3, I tried to post this earlier but this site is confusing to navigate
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E,2
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E and 2
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E and 2
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2 and E
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Only cards “2” and “E”. 2 is even, so if we turn it over and the letter is a vowel, that proves the hypothesis. And E is a vowel, so if we turn it over and the number is even, that proves the hypothesis.
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E and 3 because if you flip over E you would see if its even like the hypothesis, and flip 3 to see if it fits the hypothesis and is odd
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Cards 2 and E
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e
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E and 2
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2 and e would be enough to disprove your hypothesis but to really prove it you would have to flip all 4
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2, 3, e
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You need to turnover all 4 cards.
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